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Tolerance stackup: worst-case vs RSS

When several components assemble end-to-end, their individual tolerances stack up. The assembly gap or overall length can be anywhere within the combined tolerance range. Two methods quantify the risk: worst-case (conservative, 100% assembly guarantee) and RSS (root sum of squares, statistical, assumes tolerances are independent and normally distributed).

The formulas

Worst-case assembly tolerance: T_wc = T₁ + T₂ + T₃ + … + Tₙ RSS assembly tolerance: T_rss = √(T₁² + T₂² + T₃² + … + Tₙ²)

RSS is smaller than worst-case. The trade-off: worst-case guarantees 100% good assemblies; RSS guarantees approximately 99.73% good assemblies when each component is centered and normally distributed at ±3σ.

Worked example

Four components are assembled in series. Their nominal lengths and bilateral tolerances are:

Nominal assembly length = 10.0 + 5.0 + 8.0 + 3.0 = 26.0 Worst-case: T_wc = 0.05 + 0.03 + 0.04 + 0.02 = 0.14 Assembly range: 26.0 ± 0.14 ⇒ [25.86, 26.14] RSS: T_rss = √(0.05² + 0.03² + 0.04² + 0.02²) = √(0.0025 + 0.0009 + 0.0016 + 0.0004) = √(0.0054 + 0.0000) = √0.0054 = 0.0735 Assembly range: 26.0 ± 0.0735 ⇒ [25.9265, 26.0735]

Comparison: worst-case reserves ±0.14 (total spread 0.28). RSS needs only ±0.0735—nearly half. If the assembly gap requirement is ≥ 0.10, worst-case says the design fails (26.0 − 14 could reach 25.86, which violates no constraint here, but for a gap problem you would check the minimum gap). The key takeaway: RSS allows tighter (and cheaper) individual tolerances for the same assembly yield.

Practice problem

Three shims are stacked. Their tolerances are ±0.10, ±0.10, ±0.10. What is the RSS tolerance of the stack?

Show answer

T_rss = √(0.10² + 0.10² + 0.10²) = √0.03 = 0.1732. Compare to worst-case of 0.30. RSS is 42% smaller.

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